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Hello, People! Here is a video of Non Exact Equation, we have used inspection method to solve the problem. Please watch the video with patience. My hearty thanks to all the subscribers, supporters, viewers and well-wishers❤ With Love, Chinnaiah Kalpana🍁 Note: * Equations Reducible to Exact: Sometimes, the differential equation Mdx+Ndy=0 is not exact. Suppose that, there exists a function F(x,y) such that F(x,y)[Mdx+Ndy]=0 is exact, then F(x,y) is called an "Integrating factor" of the given differential equation Mdx+Ndy=0. * Inspection Method: An integrating factor (I.F) of given equation Mdx+Ndy=0 can be found by inspection as explained below. By rearranging the terms of the given equation or (and by dividing with a suitable function of x and y, the equation thus obtained will contain several parts integrable easily. In this connection the following exact differentials will be found useful: 1. d(xy) = xdy+ydx 2. d[x/y] = [ydx-xdy]/y^2 3. d(y/x) = [xdy-ydx]/x^2 4. d[log(xy)] = [xdy-ydx]/xy 5. d(y^2/x) = [2xydy-y^2dx]/x^2 6. d(x^2/y) = [2xydx-y^2dy]/y^2 7. d(y^2/x^2) = [2(x^2)ydy-2x(y^2)dx]/x^4 8. d(x^2/y^2) = [2(y^2)xdx-2y(x^2)dy]/y^4 9. d[log(x/y)] = (ydx-xdy)/xy 10. d[arcTan(x/y)] = (ydx-xdy)/(x^2 + y^2) 11. d[arcTan(y/x)] = (xdy-ydx)/(x^2 + y^2) 12. d(e^x/y) = [y(e^x)dx-(e^x)dy]/y^2 13. d(e^y/x) = [x(e^y)dy-(e^y)dx]/x^2 14. d[log(x/y)] = (ydx-xdy)/xy 15. d[log(y/x)] = (xdy-ydx)/xy . . . . . . * A differential equation can have more than one integrating factor. For more such videos👇 https://youtube.com/playlist?list=PL6vHH7r-gTdDeLncm6O2V3Fq0X-ZpHvs1 Stay tuned to 'Maths Pulse'. Get rid of 'Maths Phobia'. Have a happy learning! #nonexact #nonexactequation #differentialequations #mathspulse #chinnaiahkalpana #engineeringmathematics #bscmathematics #grade12maths #grade12mathematics #nonexactproblems #nonexactexamples #mathematics #inspectionmethod #differentialequationproblems